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14111155203 = 312773683413
BaseRepresentation
bin11010010010001011…
…10010010000000011
31100102102121221211220
431021011302100003
5212344423431303
610252123010123
71006454561115
oct151105622003
940372557756
1014111155203
115a91419842
122899969943
13143b659ca2
1497c16d3b5
15578c8d053
hex349172403

14111155203 has 8 divisors (see below), whose sum is σ = 18829612368. Its totient is φ = 9400067424.

The previous prime is 14111155199. The next prime is 14111155213. The reversal of 14111155203 is 30255111141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14111155203 - 22 = 14111155199 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14111155213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1837876 + ... + 1845537.

It is an arithmetic number, because the mean of its divisors is an integer number (2353701546).

Almost surely, 214111155203 is an apocalyptic number.

14111155203 is a deficient number, since it is larger than the sum of its proper divisors (4718457165).

14111155203 is a wasteful number, since it uses less digits than its factorization.

14111155203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3684693.

The product of its (nonzero) digits is 600, while the sum is 24.

Adding to 14111155203 its reverse (30255111141), we get a palindrome (44366266344).

The spelling of 14111155203 in words is "fourteen billion, one hundred eleven million, one hundred fifty-five thousand, two hundred three".

Divisors: 1 3 1277 3831 3683413 11050239 4703718401 14111155203