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141112131 = 347037377
BaseRepresentation
bin10000110100100…
…11001101000011
3100211112020110020
420122103031003
5242111042011
622000304523
73332301426
oct1032231503
9324466406
10141112131
11727216a6
123b312143
1323309604
1414a539bd
15c5c6006
hex8693343

141112131 has 4 divisors (see below), whose sum is σ = 188149512. Its totient is φ = 94074752.

The previous prime is 141112109. The next prime is 141112133. The reversal of 141112131 is 131211141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141112131 - 25 = 141112099 is a prime.

It is a super-2 number, since 2×1411121312 = 39825267030722322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 141112131.

It is not an unprimeable number, because it can be changed into a prime (141112133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23518686 + ... + 23518691.

It is an arithmetic number, because the mean of its divisors is an integer number (47037378).

Almost surely, 2141112131 is an apocalyptic number.

141112131 is a deficient number, since it is larger than the sum of its proper divisors (47037381).

141112131 is an equidigital number, since it uses as much as digits as its factorization.

141112131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47037380.

The product of its digits is 24, while the sum is 15.

The square root of 141112131 is about 11879.0627155513. The cubic root of 141112131 is about 520.6207220160.

Adding to 141112131 its reverse (131211141), we get a palindrome (272323272).

The spelling of 141112131 in words is "one hundred forty-one million, one hundred twelve thousand, one hundred thirty-one".

Divisors: 1 3 47037377 141112131