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141113005253 = 1112828455023
BaseRepresentation
bin1000001101101011111…
…1011001010011000101
3111111020102000101220222
42003122333121103011
54302444412132003
6144454301234125
713123624516403
oct2033277312305
9444212011828
10141113005253
11549336814a0
1223422562945
13103cb34739c
146b89394473
153a0d7c5c38
hex20dafd94c5

141113005253 has 4 divisors (see below), whose sum is σ = 153941460288. Its totient is φ = 128284550220.

The previous prime is 141113005217. The next prime is 141113005273. The reversal of 141113005253 is 352500311141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141113005253 - 220 = 141111956677 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141113005273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6414227501 + ... + 6414227522.

It is an arithmetic number, because the mean of its divisors is an integer number (38485365072).

Almost surely, 2141113005253 is an apocalyptic number.

It is an amenable number.

141113005253 is a deficient number, since it is larger than the sum of its proper divisors (12828455035).

141113005253 is a wasteful number, since it uses less digits than its factorization.

141113005253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12828455034.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 141113005253 its reverse (352500311141), we get a palindrome (493613316394).

The spelling of 141113005253 in words is "one hundred forty-one billion, one hundred thirteen million, five thousand, two hundred fifty-three".

Divisors: 1 11 12828455023 141113005253