14111312511240 has 768 divisors, whose sum is σ = 55150543872000. Its totient is φ = 3143336232960.

The previous prime is 14111312511229. The next prime is 14111312511301. The reversal of 14111312511240 is 4211521311141.

14111312511240 is a `hidden beast` number, since 1 + 4 + 1 + 113 + 12 + 511 + 24 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 4251674301 + ... + 4251677619.

It is an arithmetic number, because the mean of its divisors is an integer number (71810604000).

Almost surely, 2^{14111312511240} is an apocalyptic number.

14111312511240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14111312511240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27575271936000).

14111312511240 is an abundant number, since it is smaller than the sum of its proper divisors (41039231360760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14111312511240 is a wasteful number, since it uses less digits than its factorization.

14111312511240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3595 (or 3496 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 27.

Adding to 14111312511240 its reverse (4211521311141), we get a palindrome (18322833822381).

The spelling of 14111312511240 in words is "fourteen trillion, one hundred eleven billion, three hundred twelve million, five hundred eleven thousand, two hundred forty".