141113353451 has 4 divisors (see below), whose sum is σ = 161272403952. Its totient is φ = 120954302952.

The previous prime is 141113353411. The next prime is 141113353463. The reversal of 141113353451 is 154353311141.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-141113353451 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141113353411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10079525240 + ... + 10079525253.

It is an arithmetic number, because the mean of its divisors is an integer number (40318100988).

Almost surely, 2^141113353451 is an apocalyptic number.

141113353451 is a deficient number, since it is larger than the sum of its proper divisors (20159050501).

141113353451 is an equidigital number, since it uses as much as digits as its factorization.

141113353451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20159050500.

The product of its digits is 10800, while the sum is 32.

Adding to 141113353451 its reverse (154353311141), we get a palindrome (295466664592).

The spelling of 141113353451 in words is "one hundred forty-one billion, one hundred thirteen million, three hundred fifty-three thousand, four hundred fifty-one".