Base | Representation |
---|---|
bin | 100000000101011110111101… |
… | …101001111100100111111001 |
3 | 200111122101202110020200011001 |
4 | 200011132331221330213321 |
5 | 121444004123043300441 |
6 | 1220043010201405001 |
7 | 41503113464304523 |
oct | 4005367551744771 |
9 | 614571673220131 |
10 | 141114332400121 |
11 | 40a66285884613 |
12 | 139b0aa0499761 |
13 | 609804192abb2 |
14 | 26bbd82076a13 |
15 | 114aa9337e731 |
hex | 8057bda7c9f9 |
141114332400121 has 32 divisors (see below), whose sum is σ = 150728864256000. Its totient is φ = 131832173708928.
The previous prime is 141114332400053. The next prime is 141114332400131. The reversal of 141114332400121 is 121004233411141.
It is a cyclic number.
It is not a de Polignac number, because 141114332400121 - 235 = 141079972661753 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 141114332400121.
It is not an unprimeable number, because it can be changed into a prime (141114332400131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 70847010 + ... + 72811588.
It is an arithmetic number, because the mean of its divisors is an integer number (4710277008000).
Almost surely, 2141114332400121 is an apocalyptic number.
It is an amenable number.
141114332400121 is a deficient number, since it is larger than the sum of its proper divisors (9614531855879).
141114332400121 is a wasteful number, since it uses less digits than its factorization.
141114332400121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1965093.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 141114332400121 its reverse (121004233411141), we get a palindrome (262118565811262).
The spelling of 141114332400121 in words is "one hundred forty-one trillion, one hundred fourteen billion, three hundred thirty-two million, four hundred thousand, one hundred twenty-one".
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