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141114442351 = 236135410537
BaseRepresentation
bin1000001101101100010…
…0111000001001101111
3111111020111201102020211
42003123010320021233
54303000244123401
6144454352123251
713123642653241
oct2033304701157
9444214642224
10141114442351
1154934473183
1223422b36527
13103cb72b53c
146b8964a091
153a0d9ab951
hex20db13826f

141114442351 has 4 divisors (see below), whose sum is σ = 147249852912. Its totient is φ = 134979031792.

The previous prime is 141114442349. The next prime is 141114442373. The reversal of 141114442351 is 153244411141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 153244411141 = 307499167463.

It is a cyclic number.

It is not a de Polignac number, because 141114442351 - 21 = 141114442349 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141114449351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3067705246 + ... + 3067705291.

It is an arithmetic number, because the mean of its divisors is an integer number (36812463228).

Almost surely, 2141114442351 is an apocalyptic number.

141114442351 is a deficient number, since it is larger than the sum of its proper divisors (6135410561).

141114442351 is an equidigital number, since it uses as much as digits as its factorization.

141114442351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6135410560.

The product of its digits is 7680, while the sum is 31.

Adding to 141114442351 its reverse (153244411141), we get a palindrome (294358853492).

The spelling of 141114442351 in words is "one hundred forty-one billion, one hundred fourteen million, four hundred forty-two thousand, three hundred fifty-one".

Divisors: 1 23 6135410537 141114442351