Base | Representation |
---|---|
bin | 1100110101011011010011… |
… | …0111100100011100101111 |
3 | 1211222002112200111202201211 |
4 | 3031112310313210130233 |
5 | 3322202340010032310 |
6 | 50002544135215251 |
7 | 2654362365052204 |
oct | 315266467443457 |
9 | 54862480452654 |
10 | 14112002033455 |
11 | 45509592810a7 |
12 | 16bb000b17527 |
13 | 7b49aa15a921 |
14 | 36b04b4b9cab |
15 | 197143b5ac8a |
hex | cd5b4de472f |
14112002033455 has 16 divisors (see below), whose sum is σ = 17155725963264. Its totient is φ = 11142327129120.
The previous prime is 14112002033447. The next prime is 14112002033471. The reversal of 14112002033455 is 55433020021141.
It is not a de Polignac number, because 14112002033455 - 23 = 14112002033447 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16745559 + ... + 17568088.
It is an arithmetic number, because the mean of its divisors is an integer number (1072232872704).
Almost surely, 214112002033455 is an apocalyptic number.
14112002033455 is a deficient number, since it is larger than the sum of its proper divisors (3043723929809).
14112002033455 is an equidigital number, since it uses as much as digits as its factorization.
14112002033455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34314726.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14112002033455 its reverse (55433020021141), we get a palindrome (69545022054596).
The spelling of 14112002033455 in words is "fourteen trillion, one hundred twelve billion, two million, thirty-three thousand, four hundred fifty-five".
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