14112030224533 has 4 divisors (see below), whose sum is σ = 14160194150508. Its totient is φ = 14063866298560.

The previous prime is 14112030224531. The next prime is 14112030224597. The reversal of 14112030224533 is 33542203021141.

14112030224533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9212815408644 + 4899214815889 = 3035262^2 + 2213417^2 .

It is a cyclic number.

It is not a de Polignac number, because 14112030224533 - 2¹ = 14112030224531 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14112030224495 and 14112030224504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14112030224531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24081962548 + ... + 24081963133.

It is an arithmetic number, because the mean of its divisors is an integer number (3540048537627).

Almost surely, 2^{14112030224533} is an apocalyptic number.

It is an amenable number.

14112030224533 is a deficient number, since it is larger than the sum of its proper divisors (48163925975).

14112030224533 is an equidigital number, since it uses as much as digits as its factorization.

14112030224533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48163925974.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 14112030224533 its reverse (33542203021141), we get a palindrome (47654233245674).

The spelling of 14112030224533 in words is "fourteen trillion, one hundred twelve billion, thirty million, two hundred twenty-four thousand, five hundred thirty-three".