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14112030453251 = 68172720700413
BaseRepresentation
bin1100110101011011011010…
…0011111110111000000011
31211222002121122222122100212
43031112312203332320003
53322202414244001001
650002551032304335
72654363161446563
oct315266643767003
954862548878325
1014112030453251
114550973322335
1216bb00a5420ab
137b49b2ccb583
1436b051196da3
151971463c17bb
hexcd5b68fee03

14112030453251 has 4 divisors (see below), whose sum is σ = 14112051835392. Its totient is φ = 14112009071112.

The previous prime is 14112030453193. The next prime is 14112030453377. The reversal of 14112030453251 is 15235403021141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14112030453251 - 210 = 14112030452227 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14112030453751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9668480 + ... + 11031933.

It is an arithmetic number, because the mean of its divisors is an integer number (3528012958848).

Almost surely, 214112030453251 is an apocalyptic number.

14112030453251 is a deficient number, since it is larger than the sum of its proper divisors (21382141).

14112030453251 is an equidigital number, since it uses as much as digits as its factorization.

14112030453251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21382140.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 14112030453251 its reverse (15235403021141), we get a palindrome (29347433474392).

The spelling of 14112030453251 in words is "fourteen trillion, one hundred twelve billion, thirty million, four hundred fifty-three thousand, two hundred fifty-one".

Divisors: 1 681727 20700413 14112030453251