141120401230233 has 12 divisors (see below), whose sum is σ = 210869565057060. Its totient is φ = 90836120331936.

The previous prime is 141120401230201. The next prime is 141120401230313. The reversal of 141120401230233 is 332032104021141.

141120401230233 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 2 + 0 + 401 + 23 + 0 + 233 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 91139347236249 + 49981053993984 = 9546693^2 + 7069728^2 .

It is not a de Polignac number, because 141120401230233 - 2⁵ = 141120401230201 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 141120401230197 and 141120401230206.

It is not an unprimeable number, because it can be changed into a prime (141120401250233) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 270345595966 + ... + 270345596487.

It is an arithmetic number, because the mean of its divisors is an integer number (17572463754755).

Almost surely, 2^{141120401230233} is an apocalyptic number.

It is an amenable number.

141120401230233 is a deficient number, since it is larger than the sum of its proper divisors (69749163826827).

141120401230233 is a wasteful number, since it uses less digits than its factorization.

141120401230233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 540691192488 (or 540691192485 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 141120401230233 its reverse (332032104021141), we get a palindrome (473152505251374).

The spelling of 141120401230233 in words is "one hundred forty-one trillion, one hundred twenty billion, four hundred one million, two hundred thirty thousand, two hundred thirty-three".