141120404021141 has 4 divisors (see below), whose sum is σ = 141344049669984. Its totient is φ = 140896758372300.

The previous prime is 141120404021071. The next prime is 141120404021183.

141120404021141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141120404021141 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 141120404021141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141120424021141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111822823475 + ... + 111822824736.

It is an arithmetic number, because the mean of its divisors is an integer number (35336012417496).

Almost surely, 2^{141120404021141} is an apocalyptic number.

It is an amenable number.

141120404021141 is a deficient number, since it is larger than the sum of its proper divisors (223645648843).

141120404021141 is an equidigital number, since it uses as much as digits as its factorization.

141120404021141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 223645648842.

The product of its (nonzero) digits is 1024, while the sum is 26.

It can be divided in two parts, 14112040 and 4021141, that added together give a palindrome (18133181).

The spelling of 141120404021141 in words is "one hundred forty-one trillion, one hundred twenty billion, four hundred four million, twenty-one thousand, one hundred forty-one".