Base | Representation |
---|---|
bin | 1000001101101101110… |
… | …1100110001111111111 |
3 | 111111020221220122111220 |
4 | 2003123131212033333 |
5 | 4303003424010443 |
6 | 144455143044423 |
7 | 13124052023202 |
oct | 2033335461777 |
9 | 444227818456 |
10 | 141120922623 |
11 | 5493809997a |
12 | 23425140713 |
13 | 103ccb8a015 |
14 | 6b8a455939 |
15 | 3a0e33ba83 |
hex | 20db7663ff |
141120922623 has 4 divisors (see below), whose sum is σ = 188161230168. Its totient is φ = 94080615080.
The previous prime is 141120922583. The next prime is 141120922633. The reversal of 141120922623 is 326229021141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141120922623 - 26 = 141120922559 is a prime.
It is a super-2 number, since 2×1411209226232 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141120922633) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23520153768 + ... + 23520153773.
It is an arithmetic number, because the mean of its divisors is an integer number (47040307542).
Almost surely, 2141120922623 is an apocalyptic number.
141120922623 is a deficient number, since it is larger than the sum of its proper divisors (47040307545).
141120922623 is an equidigital number, since it uses as much as digits as its factorization.
141120922623 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47040307544.
The product of its (nonzero) digits is 10368, while the sum is 33.
Adding to 141120922623 its reverse (326229021141), we get a palindrome (467349943764).
The spelling of 141120922623 in words is "one hundred forty-one billion, one hundred twenty million, nine hundred twenty-two thousand, six hundred twenty-three".
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