141121143112011 has 4 divisors (see below), whose sum is σ = 188161524149352. Its totient is φ = 94080762074672.

The previous prime is 141121143112009. The next prime is 141121143112043. The reversal of 141121143112011 is 110211341121141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141121143112011 - 2¹ = 141121143112009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (141121143112811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23520190518666 + ... + 23520190518671.

It is an arithmetic number, because the mean of its divisors is an integer number (47040381037338).

Almost surely, 2^{141121143112011} is an apocalyptic number.

141121143112011 is a deficient number, since it is larger than the sum of its proper divisors (47040381037341).

141121143112011 is an equidigital number, since it uses as much as digits as its factorization.

141121143112011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47040381037340.

The product of its (nonzero) digits is 192, while the sum is 24.

Adding to 141121143112011 its reverse (110211341121141), we get a palindrome (251332484233152).

The spelling of 141121143112011 in words is "one hundred forty-one trillion, one hundred twenty-one billion, one hundred forty-three million, one hundred twelve thousand, eleven".