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1411213551205 = 5631447294311
BaseRepresentation
bin10100100010010010111…
…000011110011001100101
311222220120220021012220011
4110202102320132121211
5141110131132114310
63000145204010221
7203646121160113
oct24422270363145
94886526235804
101411213551205
114a4546294287
121a9604690971
13a30ccb51883
144c4359c8ab3
1526a9783378a
hex14892e1e665

1411213551205 has 8 divisors (see below), whose sum is σ = 1696140031104. Its totient is φ = 1127181661200.

The previous prime is 1411213551179. The next prime is 1411213551277. The reversal of 1411213551205 is 5021553121141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1411213551205 - 25 = 1411213551173 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 223644001 + ... + 223650310.

It is an arithmetic number, because the mean of its divisors is an integer number (212017503888).

Almost surely, 21411213551205 is an apocalyptic number.

It is an amenable number.

1411213551205 is a deficient number, since it is larger than the sum of its proper divisors (284926479899).

1411213551205 is an equidigital number, since it uses as much as digits as its factorization.

1411213551205 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447294947.

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 1411213551205 its reverse (5021553121141), we get a palindrome (6432766672346).

The spelling of 1411213551205 in words is "one trillion, four hundred eleven billion, two hundred thirteen million, five hundred fifty-one thousand, two hundred five".

Divisors: 1 5 631 3155 447294311 2236471555 282242710241 1411213551205