1411221413403 has 12 divisors (see below), whose sum is σ = 2038559525808. Its totient is φ = 940754923920.

The previous prime is 1411221413387. The next prime is 1411221413419. The reversal of 1411221413403 is 3043141221141.

It is a happy number.

1411221413403 is a `hidden beast` number, since 1 + 4 + 112 + 2 + 141 + 3 + 403 = 666.

It is an interprime number because it is at equal distance from previous prime (1411221413387) and next prime (1411221413419).

It is not a de Polignac number, because 1411221413403 - 2⁴ = 1411221413387 is a prime.

It is a super-2 number, since 2×1411221413403² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1411221418403) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4795143 + ... + 5080928.

It is an arithmetic number, because the mean of its divisors is an integer number (169879960484).

Almost surely, 2^{1411221413403} is an apocalyptic number.

1411221413403 is a deficient number, since it is larger than the sum of its proper divisors (627338112405).

1411221413403 is a wasteful number, since it uses less digits than its factorization.

1411221413403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9891954 (or 9891951 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 1411221413403 its reverse (3043141221141), we get a palindrome (4454362634544).

The spelling of 1411221413403 in words is "one trillion, four hundred eleven billion, two hundred twenty-one million, four hundred thirteen thousand, four hundred three".