141122413111201 has 4 divisors (see below), whose sum is σ = 141128510978752. Its totient is φ = 141116315243652.

The previous prime is 141122413111111. The next prime is 141122413111217. The reversal of 141122413111201 is 102111314221141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141122413111201 - 2³³ = 141113823176609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141122413111231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3048899061 + ... + 3048945346.

It is an arithmetic number, because the mean of its divisors is an integer number (35282127744688).

Almost surely, 2^{141122413111201} is an apocalyptic number.

It is an amenable number.

141122413111201 is a deficient number, since it is larger than the sum of its proper divisors (6097867551).

141122413111201 is an equidigital number, since it uses as much as digits as its factorization.

141122413111201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6097867550.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 141122413111201 its reverse (102111314221141), we get a palindrome (243233727332342).

The spelling of 141122413111201 in words is "one hundred forty-one trillion, one hundred twenty-two billion, four hundred thirteen million, one hundred eleven thousand, two hundred one".