Base | Representation |
---|---|
bin | 100000000101100110100000… |
… | …011000011110001011100001 |
3 | 200111200011122212121001121221 |
4 | 200011212200120132023201 |
5 | 121444122214342324210 |
6 | 1220050425551215041 |
7 | 41503521255140632 |
oct | 4005464030361341 |
9 | 614604585531557 |
10 | 141122431214305 |
11 | 40a69761403582 |
12 | 139b2580817481 |
13 | 6098a3278ab38 |
14 | 26bc50d903889 |
15 | 114adb93981da |
hex | 8059a061e2e1 |
141122431214305 has 4 divisors (see below), whose sum is σ = 169346917457172. Its totient is φ = 112897944971440.
The previous prime is 141122431214293. The next prime is 141122431214393. The reversal of 141122431214305 is 503412134221141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 29630647107216 + 111491784107089 = 5443404^2 + 10558967^2 .
It is a de Polignac number, because none of the positive numbers 2k-141122431214305 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14112243121426 + ... + 14112243121435.
It is an arithmetic number, because the mean of its divisors is an integer number (42336729364293).
Almost surely, 2141122431214305 is an apocalyptic number.
It is an amenable number.
141122431214305 is a deficient number, since it is larger than the sum of its proper divisors (28224486242867).
141122431214305 is an equidigital number, since it uses as much as digits as its factorization.
141122431214305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28224486242866.
The product of its (nonzero) digits is 23040, while the sum is 34.
Adding to 141122431214305 its reverse (503412134221141), we get a palindrome (644534565435446).
The spelling of 141122431214305 in words is "one hundred forty-one trillion, one hundred twenty-two billion, four hundred thirty-one million, two hundred fourteen thousand, three hundred five".
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