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141123562413 = 347041187471
BaseRepresentation
bin1000001101101110011…
…1101010101110101101
3111111021010212202121220
42003123213222232231
54303010112444123
6144455315413553
713124113326321
oct2033347525655
9444233782556
10141123562413
1154939632219
1223425bb42b9
13104005a2722
146b8a941981
153a0e6adce3
hex20db9eabad

141123562413 has 4 divisors (see below), whose sum is σ = 188164749888. Its totient is φ = 94082374940.

The previous prime is 141123562369. The next prime is 141123562451. The reversal of 141123562413 is 314265321141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141123562413 - 210 = 141123561389 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141123567413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23520593733 + ... + 23520593738.

It is an arithmetic number, because the mean of its divisors is an integer number (47041187472).

Almost surely, 2141123562413 is an apocalyptic number.

It is an amenable number.

141123562413 is a deficient number, since it is larger than the sum of its proper divisors (47041187475).

141123562413 is an equidigital number, since it uses as much as digits as its factorization.

141123562413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47041187474.

The product of its digits is 17280, while the sum is 33.

Adding to 141123562413 its reverse (314265321141), we get a palindrome (455388883554).

The spelling of 141123562413 in words is "one hundred forty-one billion, one hundred twenty-three million, five hundred sixty-two thousand, four hundred thirteen".

Divisors: 1 3 47041187471 141123562413