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141124122240443 = 612313510200663
BaseRepresentation
bin100000000101101000000101…
…001011001110010110111011
3200111200100000201120002101122
4200011220011023032112323
5121444134200243143233
61220051305435535455
741503611210466166
oct4005500513162673
9614610021502348
10141124122240443
1140a6a4499a7541
12139b2972bba58b
136098c41c14914
1426bc630330add
15114ae67a77d98
hex805a052ce5bb

141124122240443 has 4 divisors (see below), whose sum is σ = 143437632441168. Its totient is φ = 138810612039720.

The previous prime is 141124122240391. The next prime is 141124122240461. The reversal of 141124122240443 is 344042221421141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141124122240443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141124122242443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1156755100271 + ... + 1156755100392.

It is an arithmetic number, because the mean of its divisors is an integer number (35859408110292).

Almost surely, 2141124122240443 is an apocalyptic number.

141124122240443 is a deficient number, since it is larger than the sum of its proper divisors (2313510200725).

141124122240443 is an equidigital number, since it uses as much as digits as its factorization.

141124122240443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2313510200724.

The product of its (nonzero) digits is 49152, while the sum is 35.

Adding to 141124122240443 its reverse (344042221421141), we get a palindrome (485166343661584).

The spelling of 141124122240443 in words is "one hundred forty-one trillion, one hundred twenty-four billion, one hundred twenty-two million, two hundred forty thousand, four hundred forty-three".

Divisors: 1 61 2313510200663 141124122240443