Base | Representation |
---|---|
bin | 1100110101011101001110… |
… | …1111111011011111000010 |
3 | 1211222010212210101111211122 |
4 | 3031113103233323133002 |
5 | 3322204420122434404 |
6 | 50003111403512242 |
7 | 2654411255544251 |
oct | 315272357733702 |
9 | 54863783344748 |
10 | 14112520124354 |
11 | 45510a47744a3 |
12 | 16bb126528682 |
13 | 7b4a605a81a2 |
14 | 36b09a220798 |
15 | 1971743993be |
hex | cd5d3bfb7c2 |
14112520124354 has 4 divisors (see below), whose sum is σ = 21168780186534. Its totient is φ = 7056260062176.
The previous prime is 14112520124341. The next prime is 14112520124371. The reversal of 14112520124354 is 45342102521141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13382990608729 + 729529515625 = 3658277^2 + 854125^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3528130031087 + ... + 3528130031090.
Almost surely, 214112520124354 is an apocalyptic number.
14112520124354 is a deficient number, since it is larger than the sum of its proper divisors (7056260062180).
14112520124354 is an equidigital number, since it uses as much as digits as its factorization.
14112520124354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7056260062179.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 14112520124354 its reverse (45342102521141), we get a palindrome (59454622645495).
The spelling of 14112520124354 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, one hundred twenty-four thousand, three hundred fifty-four".
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