141125303331 has 24 divisors (see below), whose sum is σ = 205906530960. Its totient is φ = 93133656000.

The previous prime is 141125303251. The next prime is 141125303339. The reversal of 141125303331 is 133303521141.

141125303331 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 25 + 303 + 331 = 666.

141125303331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 141125303331 - 2¹⁴ = 141125286947 is a prime.

It is a super-3 number, since 3×141125303331³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 141125303295 and 141125303304.

It is not an unprimeable number, because it can be changed into a prime (141125303339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5824600 + ... + 5848778.

It is an arithmetic number, because the mean of its divisors is an integer number (8579438790).

Almost surely, 2^141125303331 is an apocalyptic number.

141125303331 is a deficient number, since it is larger than the sum of its proper divisors (64781227629).

141125303331 is a wasteful number, since it uses less digits than its factorization.

141125303331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30707 (or 30704 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 27.

Adding to 141125303331 its reverse (133303521141), we get a palindrome (274428824472).

The spelling of 141125303331 in words is "one hundred forty-one billion, one hundred twenty-five million, three hundred three thousand, three hundred thirty-one".