Base | Representation |
---|---|
bin | 11010010010011001… |
… | …10101001101011101 |
3 | 1100102120002210122010 |
4 | 31021030311031131 |
5 | 212400412033313 |
6 | 10252230341433 |
7 | 1006506353253 |
oct | 151114651535 |
9 | 40376083563 |
10 | 14113002333 |
11 | 5a924705a1 |
12 | 289a4ba879 |
13 | 143bb55971 |
14 | 97c4d05d3 |
15 | 5790054c3 |
hex | 34933535d |
14113002333 has 16 divisors (see below), whose sum is σ = 18879086016. Its totient is φ = 9377846400.
The previous prime is 14113002289. The next prime is 14113002347. The reversal of 14113002333 is 33320031141.
It is not a de Polignac number, because 14113002333 - 26 = 14113002269 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14113007333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1171366 + ... + 1183352.
It is an arithmetic number, because the mean of its divisors is an integer number (1179942876).
Almost surely, 214113002333 is an apocalyptic number.
It is an amenable number.
14113002333 is a deficient number, since it is larger than the sum of its proper divisors (4766083683).
14113002333 is a wasteful number, since it uses less digits than its factorization.
14113002333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13244.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 14113002333 its reverse (33320031141), we get a palindrome (47433033474).
The spelling of 14113002333 in words is "fourteen billion, one hundred thirteen million, two thousand, three hundred thirty-three".
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