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141130243052511 = 3291622186701753
BaseRepresentation
bin100000000101101101110010…
…000000010001001111011111
3200111200220211021221120001220
4200011231302000101033133
5121444234214210140021
61220054201050104423
741504215662520266
oct4005556200211737
9614626737846056
10141130243052511
1140a71aaaa44209
12139b3ba0a1b113
1360996a90300cb
1426bca511cb5dd
15114b1c50c6cc6
hex805b720113df

141130243052511 has 8 divisors (see below), whose sum is σ = 194662404210480. Its totient is φ = 90842455298112.

The previous prime is 141130243052471. The next prime is 141130243052527. The reversal of 141130243052511 is 115250342031141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 141130243052511 - 210 = 141130243051487 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141130243052111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 811093350790 + ... + 811093350963.

It is an arithmetic number, because the mean of its divisors is an integer number (24332800526310).

Almost surely, 2141130243052511 is an apocalyptic number.

141130243052511 is a deficient number, since it is larger than the sum of its proper divisors (53532161157969).

141130243052511 is a wasteful number, since it uses less digits than its factorization.

141130243052511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1622186701785.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 141130243052511 its reverse (115250342031141), we get a palindrome (256380585083652).

The spelling of 141130243052511 in words is "one hundred forty-one trillion, one hundred thirty billion, two hundred forty-three million, fifty-two thousand, five hundred eleven".

Divisors: 1 3 29 87 1622186701753 4866560105259 47043414350837 141130243052511