14113025102141 has 4 divisors (see below), whose sum is σ = 16129171545312. Its totient is φ = 12096878658972.

The previous prime is 14113025102003. The next prime is 14113025102147. The reversal of 14113025102141 is 14120152031141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14113025102141 - 2³⁴ = 14095845232957 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14113025102141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113025102147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1008073221575 + ... + 1008073221588.

It is an arithmetic number, because the mean of its divisors is an integer number (4032292886328).

Almost surely, 2^{14113025102141} is an apocalyptic number.

It is an amenable number.

14113025102141 is a deficient number, since it is larger than the sum of its proper divisors (2016146443171).

14113025102141 is an equidigital number, since it uses as much as digits as its factorization.

14113025102141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2016146443170.

The product of its (nonzero) digits is 960, while the sum is 26.

Adding to 14113025102141 its reverse (14120152031141), we get a palindrome (28233177133282).

The spelling of 14113025102141 in words is "fourteen trillion, one hundred thirteen billion, twenty-five million, one hundred two thousand, one hundred forty-one".