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14113031321111 = 254922621244759
BaseRepresentation
bin1100110101011111001000…
…1101111111011000010111
31211222012012102021222221212
43031113302031333120113
53322211442004233421
650003234224332035
72654430033623642
oct315276215773027
954865172258855
1014113031321111
114551337289158
1216bb24977401b
137b4b12480788
1436b10808ca59
151971a41c4e5b
hexcd5f237f617

14113031321111 has 8 divisors (see below), whose sum is σ = 14119249836000. Its totient is φ = 14106813346080.

The previous prime is 14113031321099. The next prime is 14113031321161. The reversal of 14113031321111 is 11112313031141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14113031321111 - 26 = 14113031321047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113031321161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57538550 + ... + 57783308.

It is an arithmetic number, because the mean of its divisors is an integer number (1764906229500).

Almost surely, 214113031321111 is an apocalyptic number.

14113031321111 is a deficient number, since it is larger than the sum of its proper divisors (6218514889).

14113031321111 is a wasteful number, since it uses less digits than its factorization.

14113031321111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 269929.

The product of its (nonzero) digits is 216, while the sum is 23.

Adding to 14113031321111 its reverse (11112313031141), we get a palindrome (25225344352252).

The spelling of 14113031321111 in words is "fourteen trillion, one hundred thirteen billion, thirty-one million, three hundred twenty-one thousand, one hundred eleven".

Divisors: 1 2549 22621 244759 57660929 623890691 5536693339 14113031321111