Base | Representation |
---|---|
bin | 100000000101101101110110… |
… | …111010100111000101100011 |
3 | 200111200221001001000001022110 |
4 | 200011231312322213011203 |
5 | 121444234401304031303 |
6 | 1220054213152210403 |
7 | 41504221013111340 |
oct | 4005556672470543 |
9 | 614627031001273 |
10 | 141130325455203 |
11 | 40a72042506607 |
12 | 139b4004539a03 |
13 | 60996c0121cb6 |
14 | 26bca5c11b7c7 |
15 | 114b1cc452703 |
hex | 805b76ea7163 |
141130325455203 has 32 divisors (see below), whose sum is σ = 220303492964352. Its totient is φ = 78678035251200.
The previous prime is 141130325455177. The next prime is 141130325455213. The reversal of 141130325455203 is 302554523031141.
141130325455203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 141130325455203 - 212 = 141130325451107 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141130325455213) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 79072483 + ... + 80837603.
It is an arithmetic number, because the mean of its divisors is an integer number (6884484155136).
Almost surely, 2141130325455203 is an apocalyptic number.
141130325455203 is a deficient number, since it is larger than the sum of its proper divisors (79173167509149).
141130325455203 is a wasteful number, since it uses less digits than its factorization.
141130325455203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1858035.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 141130325455203 its reverse (302554523031141), we get a palindrome (443684848486344).
The spelling of 141130325455203 in words is "one hundred forty-one trillion, one hundred thirty billion, three hundred twenty-five million, four hundred fifty-five thousand, two hundred three".
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