Base | Representation |
---|---|
bin | 1100110101011111001001… |
… | …0110011111111010001111 |
3 | 1211222012012120111022110222 |
4 | 3031113302112133322033 |
5 | 3322211443042122003 |
6 | 50003234344221555 |
7 | 2654430061603355 |
oct | 315276226377217 |
9 | 54865176438428 |
10 | 14113033551503 |
11 | 4551338571957 |
12 | 16bb24a46a8bb |
13 | 7b4b12a81a33 |
14 | 36b1084ad7d5 |
15 | 1971a44b5c38 |
hex | cd5f259fe8f |
14113033551503 has 4 divisors (see below), whose sum is σ = 14113176311520. Its totient is φ = 14112890791488.
The previous prime is 14113033551437. The next prime is 14113033551511. The reversal of 14113033551503 is 30515533031141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14113033551503 - 218 = 14113033289359 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14113093551503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71231618 + ... + 71429471.
It is an arithmetic number, because the mean of its divisors is an integer number (3528294077880).
Almost surely, 214113033551503 is an apocalyptic number.
14113033551503 is a deficient number, since it is larger than the sum of its proper divisors (142760017).
14113033551503 is an equidigital number, since it uses as much as digits as its factorization.
14113033551503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142760016.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 14113033551503 its reverse (30515533031141), we get a palindrome (44628566582644).
The spelling of 14113033551503 in words is "fourteen trillion, one hundred thirteen billion, thirty-three million, five hundred fifty-one thousand, five hundred three".
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