141131101440431 has 4 divisors (see below), whose sum is σ = 141131816439264. Its totient is φ = 141130386441600.

The previous prime is 141131101440377. The next prime is 141131101440457. The reversal of 141131101440431 is 134044101131141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141131101440431 - 2²² = 141131097246127 is a prime.

It is a super-2 number, since 2×141131101440431² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141131101440394 and 141131101440403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141131101440731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357203255 + ... + 357598136.

It is an arithmetic number, because the mean of its divisors is an integer number (35282954109816).

Almost surely, 2^{141131101440431} is an apocalyptic number.

141131101440431 is a deficient number, since it is larger than the sum of its proper divisors (714998833).

141131101440431 is an equidigital number, since it uses as much as digits as its factorization.

141131101440431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 714998832.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 141131101440431 its reverse (134044101131141), we get a palindrome (275175202571572).

The spelling of 141131101440431 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred one million, four hundred forty thousand, four hundred thirty-one".