1411320235135 has 8 divisors (see below), whose sum is σ = 1693612133136. Its totient is φ = 1129037620800.

The previous prime is 1411320235133. The next prime is 1411320235141. The reversal of 1411320235135 is 5315320231141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1411320235135 - 2¹ = 1411320235133 is a prime.

It is a super-3 number, since 3×1411320235135³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1411320235097 and 1411320235106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411320235133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1981966 + ... + 2598235.

It is an arithmetic number, because the mean of its divisors is an integer number (211701516642).

Almost surely, 2^{1411320235135} is an apocalyptic number.

1411320235135 is a deficient number, since it is larger than the sum of its proper divisors (282291898001).

1411320235135 is an equidigital number, since it uses as much as digits as its factorization.

1411320235135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4641833.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 1411320235135 its reverse (5315320231141), we get a palindrome (6726640466276).

The spelling of 1411320235135 in words is "one trillion, four hundred eleven billion, three hundred twenty million, two hundred thirty-five thousand, one hundred thirty-five".