141132120230133 has 12 divisors (see below), whose sum is σ = 211407785036448. Its totient is φ = 94088080153260.

The previous prime is 141132120230093. The next prime is 141132120230141. The reversal of 141132120230133 is 331032021231141.

141132120230133 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 321 + 2 + 0 + 2 + 301 + 33 = 666.

It is not a de Polignac number, because 141132120230133 - 2¹³ = 141132120221941 is a prime.

It is a super-3 number, since 3×141132120230133³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 141132120230097 and 141132120230106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141132120230183) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 290395308873 + ... + 290395309358.

It is an arithmetic number, because the mean of its divisors is an integer number (17617315419704).

Almost surely, 2^{141132120230133} is an apocalyptic number.

It is an amenable number.

141132120230133 is a deficient number, since it is larger than the sum of its proper divisors (70275664806315).

141132120230133 is an frugal number, since it uses more digits than its factorization.

141132120230133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 580790618246 (or 580790618234 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 141132120230133 its reverse (331032021231141), we get a palindrome (472164141461274).

The spelling of 141132120230133 in words is "one hundred forty-one trillion, one hundred thirty-two billion, one hundred twenty million, two hundred thirty thousand, one hundred thirty-three".