14113224001 has 4 divisors (see below), whose sum is σ = 14116563904. Its totient is φ = 14109884100.

The previous prime is 14113223981. The next prime is 14113224023. The reversal of 14113224001 is 10042231141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14113224001 - 2¹⁵ = 14113191233 is a prime.

It is a super-3 number, since 3×14113224001³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14113224001.

It is not an unprimeable number, because it can be changed into a prime (14113222001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1663605 + ... + 1672066.

It is an arithmetic number, because the mean of its divisors is an integer number (3529140976).

Almost surely, 2^14113224001 is an apocalyptic number.

It is an amenable number.

14113224001 is a deficient number, since it is larger than the sum of its proper divisors (3339903).

14113224001 is an equidigital number, since it uses as much as digits as its factorization.

14113224001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3339902.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 14113224001 its reverse (10042231141), we get a palindrome (24155455142).

The spelling of 14113224001 in words is "fourteen billion, one hundred thirteen million, two hundred twenty-four thousand, one".