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14113224023 is a prime number
BaseRepresentation
bin11010010010011011…
…01011010101010111
31100102120112001201212
431021031223111113
5212400441132043
610252235212035
71006511265503
oct151115532527
940376461655
1014113224023
115a92602108
12289a5a701b
13143bc02842
1497c54b303
1557904b018
hex34936b557

14113224023 has 2 divisors, whose sum is σ = 14113224024. Its totient is φ = 14113224022.

The previous prime is 14113223981. The next prime is 14113224029. The reversal of 14113224023 is 32042231141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14113224023 - 28 = 14113223767 is a prime.

It is a super-3 number, since 3×141132240233 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14113224023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14113224029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056612011 + 7056612012.

It is an arithmetic number, because the mean of its divisors is an integer number (7056612012).

Almost surely, 214113224023 is an apocalyptic number.

14113224023 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113224023 is an equidigital number, since it uses as much as digits as its factorization.

14113224023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14113224023 its reverse (32042231141), we get a palindrome (46155455164).

The spelling of 14113224023 in words is "fourteen billion, one hundred thirteen million, two hundred twenty-four thousand, twenty-three".