Base | Representation |
---|---|
bin | 1100110101011111111001… |
… | …0011001110011111010111 |
3 | 1211222012201112201011222122 |
4 | 3031113332103032133113 |
5 | 3322212400402122221 |
6 | 50003310305050155 |
7 | 2654435044552466 |
oct | 315277623163727 |
9 | 54865645634878 |
10 | 14113234020311 |
11 | 4551430745058 |
12 | 16bb2a562695b |
13 | 7b4b4547152a |
14 | 36b126d749dd |
15 | 1971b6db3eab |
hex | cd5fe4ce7d7 |
14113234020311 has 4 divisors (see below), whose sum is σ = 14113257766872. Its totient is φ = 14113210273752.
The previous prime is 14113234020299. The next prime is 14113234020323. The reversal of 14113234020311 is 11302043231141.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (14113234020299) and next prime (14113234020323).
It is a cyclic number.
It is not a de Polignac number, because 14113234020311 - 242 = 9715187509207 is a prime.
It is a super-3 number, since 3×141132340203113 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14113234010311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10958285 + ... + 12178278.
It is an arithmetic number, because the mean of its divisors is an integer number (3528314441718).
Almost surely, 214113234020311 is an apocalyptic number.
14113234020311 is a deficient number, since it is larger than the sum of its proper divisors (23746561).
14113234020311 is an equidigital number, since it uses as much as digits as its factorization.
14113234020311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23746560.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 14113234020311 its reverse (11302043231141), we get a palindrome (25415277251452).
The spelling of 14113234020311 in words is "fourteen trillion, one hundred thirteen billion, two hundred thirty-four million, twenty thousand, three hundred eleven".
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