Base | Representation |
---|---|
bin | 10100100010011001111… |
… | …100010111100110000111 |
3 | 11222220220011011200010200 |
4 | 110202121330113212013 |
5 | 141110401443344143 |
6 | 3000205035021543 |
7 | 203652060112104 |
oct | 24423174274607 |
9 | 4886804150120 |
10 | 1411332012423 |
11 | 4a45a7144a13 |
12 | 1a963829a8b3 |
13 | a311b55a278 |
14 | 4c447623aab |
15 | 26aa2e331d3 |
hex | 14899f17987 |
1411332012423 has 12 divisors (see below), whose sum is σ = 2043320599008. Its totient is φ = 938704970880.
The previous prime is 1411332012359. The next prime is 1411332012437. The reversal of 1411332012423 is 3242102331141.
1411332012423 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 33 + 201 + 2 + 423 = 666.
It is not a de Polignac number, because 1411332012423 - 26 = 1411332012359 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1411332012473) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 181915690 + ... + 181923447.
It is an arithmetic number, because the mean of its divisors is an integer number (170276716584).
Almost surely, 21411332012423 is an apocalyptic number.
1411332012423 is a deficient number, since it is larger than the sum of its proper divisors (631988586585).
1411332012423 is a wasteful number, since it uses less digits than its factorization.
1411332012423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 363839574 (or 363839571 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 1411332012423 its reverse (3242102331141), we get a palindrome (4653434343564).
The spelling of 1411332012423 in words is "one trillion, four hundred eleven billion, three hundred thirty-two million, twelve thousand, four hundred twenty-three".
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