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1411340400403 = 58722349107581
BaseRepresentation
bin10100100010011010011…
…100010111011100010011
311222220220201221211021121
4110202122130113130103
5141110411120303103
63000205534503111
7203652221315623
oct24423234273423
94886821854247
101411340400403
114a4600953a2a
121a963b064a97
13a312020617b
144c4487a8883
1526aa3a3d6bd
hex1489a717713

1411340400403 has 8 divisors (see below), whose sum is σ = 1413821127600. Its totient is φ = 1408859934240.

The previous prime is 1411340400343. The next prime is 1411340400409. The reversal of 1411340400403 is 3040040431141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1411340400403 - 213 = 1411340392211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1411340400409) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13065073 + ... + 13172653.

It is an arithmetic number, because the mean of its divisors is an integer number (176727640950).

Almost surely, 21411340400403 is an apocalyptic number.

1411340400403 is a deficient number, since it is larger than the sum of its proper divisors (2480727197).

1411340400403 is a wasteful number, since it uses less digits than its factorization.

1411340400403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130517.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1411340400403 its reverse (3040040431141), we get a palindrome (4451380831544).

The spelling of 1411340400403 in words is "one trillion, four hundred eleven billion, three hundred forty million, four hundred thousand, four hundred three".

Divisors: 1 587 22349 107581 13118863 63150047 2404327769 1411340400403