1411344013402 has 4 divisors (see below), whose sum is σ = 2117016020106. Its totient is φ = 705672006700.

The previous prime is 1411344013399. The next prime is 1411344013421. The reversal of 1411344013402 is 2043104431141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1385326646001 + 26017367401 = 1176999^2 + 161299^2 .

It is a super-2 number, since 2×1411344013402² (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 352836003349 + ... + 352836003352.

Almost surely, 2^{1411344013402} is an apocalyptic number.

1411344013402 is a deficient number, since it is larger than the sum of its proper divisors (705672006704).

1411344013402 is an equidigital number, since it uses as much as digits as its factorization.

1411344013402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 705672006703.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1411344013402 its reverse (2043104431141), we get a palindrome (3454448444543).

The spelling of 1411344013402 in words is "one trillion, four hundred eleven billion, three hundred forty-four million, thirteen thousand, four hundred two".