14113550143503 has 8 divisors (see below), whose sum is σ = 20908963175600. Its totient is φ = 9409033428984.

The previous prime is 14113550143499. The next prime is 14113550143513. The reversal of 14113550143503 is 30534105531141.

14113550143503 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 3 + 5 + 5 + 0 + 143 + 503 = 666.

It is not a de Polignac number, because 14113550143503 - 2² = 14113550143499 is a prime.

It is a super-3 number, since 3×14113550143503³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113550143513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 261362039668 + ... + 261362039721.

It is an arithmetic number, because the mean of its divisors is an integer number (2613620396950).

Almost surely, 2^{14113550143503} is an apocalyptic number.

14113550143503 is a deficient number, since it is larger than the sum of its proper divisors (6795413032097).

14113550143503 is an equidigital number, since it uses as much as digits as its factorization.

14113550143503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 522724079398 (or 522724079392 counting only the distinct ones).

The product of its (nonzero) digits is 54000, while the sum is 36.

Adding to 14113550143503 its reverse (30534105531141), we get a palindrome (44647655674644).

The spelling of 14113550143503 in words is "fourteen trillion, one hundred thirteen billion, five hundred fifty million, one hundred forty-three thousand, five hundred three".