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14114011022103 = 334793887144409
BaseRepresentation
bin1100110101100010110010…
…0111010000001100010111
31211222021201200202222001210
43031120230213100030113
53322220443310201403
650003515342552503
72654463231142026
oct315305447201427
954867650688053
1014114011022103
11455179a2a7aa3
1216bb481898733
137b4c3a4313c5
1436b19c2348bd
151972101e6b03
hexcd62c9d0317

14114011022103 has 16 divisors (see below), whose sum is σ = 18873245583360. Its totient is φ = 9382059525696.

The previous prime is 14114011022053. The next prime is 14114011022113. The reversal of 14114011022103 is 30122011041141.

It is not a de Polignac number, because 14114011022103 - 212 = 14114011018007 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14114011022103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14114011022113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 97664163 + ... + 97808571.

It is an arithmetic number, because the mean of its divisors is an integer number (1179577848960).

Almost surely, 214114011022103 is an apocalyptic number.

14114011022103 is a deficient number, since it is larger than the sum of its proper divisors (4759234561257).

14114011022103 is a wasteful number, since it uses less digits than its factorization.

14114011022103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 238646.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 14114011022103 its reverse (30122011041141), we get a palindrome (44236022063244).

The spelling of 14114011022103 in words is "fourteen trillion, one hundred fourteen billion, eleven million, twenty-two thousand, one hundred three".

Divisors: 1 3 347 1041 93887 144409 281661 433227 32578789 50109923 97736367 150329769 13558127783 40674383349 4704670340701 14114011022103