1411422433 has 4 divisors (see below), whose sum is σ = 1494447300. Its totient is φ = 1328397568.

The previous prime is 1411422323. The next prime is 1411422437. The reversal of 1411422433 is 3342241141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 486775969 + 924646464 = 22063^2 + 30408^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411422433 - 2¹⁷ = 1411291361 is a prime.

It is a super-2 number, since 2×1411422433² = 3984226568751278978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1411422398 and 1411422407.

It is not an unprimeable number, because it can be changed into a prime (1411422437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41512408 + ... + 41512441.

It is an arithmetic number, because the mean of its divisors is an integer number (373611825).

Almost surely, 2^1411422433 is an apocalyptic number.

It is an amenable number.

1411422433 is a deficient number, since it is larger than the sum of its proper divisors (83024867).

1411422433 is an equidigital number, since it uses as much as digits as its factorization.

1411422433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83024866.

The product of its digits is 2304, while the sum is 25.

The square root of 1411422433 is about 37568.9024726568. The cubic root of 1411422433 is about 1121.7231216904.

Adding to 1411422433 its reverse (3342241141), we get a palindrome (4753663574).

The spelling of 1411422433 in words is "one billion, four hundred eleven million, four hundred twenty-two thousand, four hundred thirty-three".