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141142330111 = 319973441107
BaseRepresentation
bin1000001101110010111…
…1010000101011111111
3111111022110012021001211
42003130233100223333
54303024414030421
6144501225545251
713124432003536
oct2033457205377
9444273167054
10141142330111
1154949190712
1223430345227
1310404443c83
146b8d22931d
153a111699e1
hex20dcbd0aff

141142330111 has 4 divisors (see below), whose sum is σ = 141143091192. Its totient is φ = 141141569032.

The previous prime is 141142330073. The next prime is 141142330123. The reversal of 141142330111 is 111033241141.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 141142330111 - 29 = 141142329599 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141142330171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99420 + ... + 540526.

It is an arithmetic number, because the mean of its divisors is an integer number (35285772798).

Almost surely, 2141142330111 is an apocalyptic number.

141142330111 is a deficient number, since it is larger than the sum of its proper divisors (761081).

141142330111 is an equidigital number, since it uses as much as digits as its factorization.

141142330111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 761080.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 141142330111 its reverse (111033241141), we get a palindrome (252175571252).

The spelling of 141142330111 in words is "one hundred forty-one billion, one hundred forty-two million, three hundred thirty thousand, one hundred eleven".

Divisors: 1 319973 441107 141142330111