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141142531243 = 7163712317177
BaseRepresentation
bin1000001101110011000…
…0000001110010101011
3111111022110120110222011
42003130300001302223
54303024441444433
6144501234140351
713124433502120
oct2033460016253
9444273513864
10141142531243
115494930883a
12234304216b7
13104044b469c
146b8d27c747
153a111a93cd
hex20dcc01cab

141142531243 has 8 divisors (see below), whose sum is σ = 161404300512. Its totient is φ = 120905399616.

The previous prime is 141142531223. The next prime is 141142531253. The reversal of 141142531243 is 342135241141.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141142531243 - 217 = 141142400171 is a prime.

It is a super-2 number, since 2×1411425312432 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (141142531223) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6147130 + ... + 6170047.

It is an arithmetic number, because the mean of its divisors is an integer number (20175537564).

Almost surely, 2141142531243 is an apocalyptic number.

141142531243 is a deficient number, since it is larger than the sum of its proper divisors (20261769269).

141142531243 is a wasteful number, since it uses less digits than its factorization.

141142531243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12318821.

The product of its digits is 11520, while the sum is 31.

Adding to 141142531243 its reverse (342135241141), we get a palindrome (483277772384).

The spelling of 141142531243 in words is "one hundred forty-one billion, one hundred forty-two million, five hundred thirty-one thousand, two hundred forty-three".

Divisors: 1 7 1637 11459 12317177 86220239 20163218749 141142531243