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14114302543 = 112621489553
BaseRepresentation
bin11010010010100011…
…10010101001001111
31100102122112212012001
431021101302221033
5212401230140133
610252314253131
71006523410045
oct151121625117
940378485161
1014114302543
115a93179450
12289aa271a7
13143c1bc713
1497c74c395
155791b087d
hex349472a4f

14114302543 has 8 divisors (see below), whose sum is σ = 15403327056. Its totient is φ = 12826262400.

The previous prime is 14114302529. The next prime is 14114302571. The reversal of 14114302543 is 34520341141.

14114302543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14114302543 - 29 = 14114302031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14114302583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 215946 + ... + 273607.

It is an arithmetic number, because the mean of its divisors is an integer number (1925415882).

Almost surely, 214114302543 is an apocalyptic number.

14114302543 is a deficient number, since it is larger than the sum of its proper divisors (1289024513).

14114302543 is a wasteful number, since it uses less digits than its factorization.

14114302543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 492185.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 14114302543 its reverse (34520341141), we get a palindrome (48634643684).

The spelling of 14114302543 in words is "fourteen billion, one hundred fourteen million, three hundred two thousand, five hundred forty-three".

Divisors: 1 11 2621 28831 489553 5385083 1283118413 14114302543