141143312132001 has 10 divisors (see below), whose sum is σ = 210843713184962. Its totient is φ = 94095541421280.

The previous prime is 141143312131979. The next prime is 141143312132023. The reversal of 141143312132001 is 100231213341141.

141143312132001 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 4 + 331 + 2 + 1 + 320 + 0 + 1 = 666.

It is an interprime number because it is at equal distance from previous prime (141143312131979) and next prime (141143312132023).

It can be written as a sum of positive squares in only one way, i.e., 115874352605025 + 25268959526976 = 10764495^2 + 5026824^2 .

It is not a de Polignac number, because 141143312132001 - 2⁶ = 141143312131937 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141143312134001) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 871255013080 + ... + 871255013241.

Almost surely, 2^{141143312132001} is an apocalyptic number.

It is an amenable number.

141143312132001 is a deficient number, since it is larger than the sum of its proper divisors (69700401052961).

141143312132001 is an equidigital number, since it uses as much as digits as its factorization.

141143312132001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1742510026333 (or 1742510026324 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 141143312132001 its reverse (100231213341141), we get a palindrome (241374525473142).

The spelling of 141143312132001 in words is "one hundred forty-one trillion, one hundred forty-three billion, three hundred twelve million, one hundred thirty-two thousand, one".