14114440663341 has 4 divisors (see below), whose sum is σ = 18819254217792. Its totient is φ = 9409627108892.

The previous prime is 14114440663333. The next prime is 14114440663423. The reversal of 14114440663341 is 14336604441141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14114440663341 - 2³ = 14114440663333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14114440663293 and 14114440663302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14114440663321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2352406777221 + ... + 2352406777226.

It is an arithmetic number, because the mean of its divisors is an integer number (4704813554448).

Almost surely, 2^{14114440663341} is an apocalyptic number.

It is an amenable number.

14114440663341 is a deficient number, since it is larger than the sum of its proper divisors (4704813554451).

14114440663341 is an equidigital number, since it uses as much as digits as its factorization.

14114440663341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4704813554450.

The product of its (nonzero) digits is 331776, while the sum is 42.

The spelling of 14114440663341 in words is "fourteen trillion, one hundred fourteen billion, four hundred forty million, six hundred sixty-three thousand, three hundred forty-one".