1411500505501 has 4 divisors (see below), whose sum is σ = 1457032779904. Its totient is φ = 1365968231100.

The previous prime is 1411500505487. The next prime is 1411500505537. The reversal of 1411500505501 is 1055050051141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411500505501 is a prime.

It is a super-2 number, since 2×1411500505501² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1411500505501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411500505561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22766137155 + ... + 22766137216.

It is an arithmetic number, because the mean of its divisors is an integer number (364258194976).

Almost surely, 2^{1411500505501} is an apocalyptic number.

It is an amenable number.

1411500505501 is a deficient number, since it is larger than the sum of its proper divisors (45532274403).

1411500505501 is an equidigital number, since it uses as much as digits as its factorization.

1411500505501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45532274402.

The product of its (nonzero) digits is 2500, while the sum is 28.

Adding to 1411500505501 its reverse (1055050051141), we get a palindrome (2466550556642).

The spelling of 1411500505501 in words is "one trillion, four hundred eleven billion, five hundred million, five hundred five thousand, five hundred one".