14115243534233 has 4 divisors (see below), whose sum is σ = 14222993485008. Its totient is φ = 14007493583460.

The previous prime is 14115243534211. The next prime is 14115243534239. The reversal of 14115243534233 is 33243534251141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14115243534233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14115243534239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53874975191 + ... + 53874975452.

It is an arithmetic number, because the mean of its divisors is an integer number (3555748371252).

Almost surely, 2^{14115243534233} is an apocalyptic number.

It is an amenable number.

14115243534233 is a deficient number, since it is larger than the sum of its proper divisors (107749950775).

14115243534233 is a wasteful number, since it uses less digits than its factorization.

14115243534233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107749950774.

The product of its digits is 518400, while the sum is 41.

Adding to 14115243534233 its reverse (33243534251141), we get a palindrome (47358777785374).

The spelling of 14115243534233 in words is "fourteen trillion, one hundred fifteen billion, two hundred forty-three million, five hundred thirty-four thousand, two hundred thirty-three".