Base | Representation |
---|---|
bin | 10100100010100101111… |
… | …000100001100110001111 |
3 | 11222221102010002221010022 |
4 | 110202211320201212033 |
5 | 141111304234101112 |
6 | 3000240552332355 |
7 | 203660041565342 |
oct | 24424570414617 |
9 | 4887363087108 |
10 | 1411532331407 |
11 | 4a469a2255a0 |
12 | 1a96933a40bb |
13 | a3150bc6803 |
14 | 4c46608a459 |
15 | 26ab5801d72 |
hex | 148a5e2198f |
1411532331407 has 8 divisors (see below), whose sum is σ = 1539883515600. Its totient is φ = 1283186157760.
The previous prime is 1411532331389. The next prime is 1411532331487. The reversal of 1411532331407 is 7041332351141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1411532331407 - 218 = 1411532069263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1411532331487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 651032 + ... + 1801917.
It is an arithmetic number, because the mean of its divisors is an integer number (192485439450).
Almost surely, 21411532331407 is an apocalyptic number.
1411532331407 is a deficient number, since it is larger than the sum of its proper divisors (128351184193).
1411532331407 is a wasteful number, since it uses less digits than its factorization.
1411532331407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2505273.
The product of its (nonzero) digits is 30240, while the sum is 35.
Adding to 1411532331407 its reverse (7041332351141), we get a palindrome (8452864682548).
The spelling of 1411532331407 in words is "one trillion, four hundred eleven billion, five hundred thirty-two million, three hundred thirty-one thousand, four hundred seven".
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