Base | Representation |
---|---|
bin | 100000000110000101001111… |
… | …000110110010101000101101 |
3 | 200111210022211102200002212001 |
4 | 200012011033012302220231 |
5 | 122000142303401111443 |
6 | 1220113524053212301 |
7 | 41506100035603153 |
oct | 4006051706625055 |
9 | 614708742602761 |
10 | 141155427363373 |
11 | 40a81753917765 |
12 | 139b8a4b031091 |
13 | 609bb907b96b7 |
14 | 26bdd5dc313d3 |
15 | 114bb9b054d4d |
hex | 80614f1b2a2d |
141155427363373 has 4 divisors (see below), whose sum is σ = 141186663355360. Its totient is φ = 141124191371388.
The previous prime is 141155427363331. The next prime is 141155427363439. The reversal of 141155427363373 is 373363724551141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 141155427363373 - 217 = 141155427232301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141155427363323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15617989215 + ... + 15617998252.
It is an arithmetic number, because the mean of its divisors is an integer number (35296665838840).
Almost surely, 2141155427363373 is an apocalyptic number.
It is an amenable number.
141155427363373 is a deficient number, since it is larger than the sum of its proper divisors (31235991987).
141155427363373 is an equidigital number, since it uses as much as digits as its factorization.
141155427363373 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31235991986.
The product of its digits is 19051200, while the sum is 55.
The spelling of 141155427363373 in words is "one hundred forty-one trillion, one hundred fifty-five billion, four hundred twenty-seven million, three hundred sixty-three thousand, three hundred seventy-three".
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