1412002166241 has 4 divisors (see below), whose sum is σ = 1882669554992. Its totient is φ = 941334777492.

The previous prime is 1412002166209. The next prime is 1412002166261. The reversal of 1412002166241 is 1426612002141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1412002166241 - 2⁵ = 1412002166209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1412002166199 and 1412002166208.

It is not an unprimeable number, because it can be changed into a prime (1412002166261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235333694371 + ... + 235333694376.

It is an arithmetic number, because the mean of its divisors is an integer number (470667388748).

Almost surely, 2^{1412002166241} is an apocalyptic number.

It is an amenable number.

1412002166241 is a deficient number, since it is larger than the sum of its proper divisors (470667388751).

1412002166241 is an equidigital number, since it uses as much as digits as its factorization.

1412002166241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 470667388750.

The product of its (nonzero) digits is 4608, while the sum is 30.

Adding to 1412002166241 its reverse (1426612002141), we get a palindrome (2838614168382).

The spelling of 1412002166241 in words is "one trillion, four hundred twelve billion, two million, one hundred sixty-six thousand, two hundred forty-one".